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Chapter 2 Electrochemistry
Electrochemical Cells
Electrochemical cells convert chemical energy into electrical energy (galvanic cells) or use electrical energy to drive non-spontaneous chemical reactions (electrolytic cells). A galvanic cell, like the Daniell cell (Zn-Cu), utilizes a spontaneous redox reaction to generate electricity. An electrolytic cell uses an external voltage source to force a non-spontaneous reaction to occur.
A galvanic cell comprises two half-cells, each consisting of an electrode immersed in an electrolyte. The two half-cells are connected externally by a wire (with a voltmeter) and internally by a salt bridge or by dipping both electrodes in the same electrolyte. The half-cell where oxidation occurs is the anode (negative potential), and where reduction occurs is the cathode (positive potential). The potential difference between electrodes is the cell potential (emf), measured in volts. The standard cell potential ($E^o_{cell}$) is measured when all species are at unit concentration and gases are at 1 bar pressure.
The standard hydrogen electrode (SHE), with a standard electrode potential of 0 V, serves as a reference to measure the standard electrode potentials ($E^o$) of other half-cells.
Galvanic Cells
Galvanic cells convert chemical energy from spontaneous redox reactions into electrical energy. The Daniell cell (Zn + Cu²⁺ → Zn²⁺ + Cu) is a common example, with a standard cell potential ($E^o_{cell}$) of 1.1 V. It's represented as Zn(s)|Zn²⁺(aq)||Cu²⁺(aq)|Cu(s), where the anode (oxidation) is on the left and the cathode (reduction) is on the right. The cell potential is $E_{cell} = E_{cathode} - E_{anode}$.
Measurement Of Electrode Potential
The potential difference between an electrode and its electrolyte solution is the electrode potential. Standard electrode potential ($E^o$) is measured when concentrations of all species are unity and temperature is 298 K. The Standard Hydrogen Electrode (SHE), Pt(s)|H₂(g, 1 bar)|H⁺(aq, 1 M), is assigned a standard electrode potential of 0 V. By combining a half-cell with SHE, its standard electrode potential can be measured. A positive $E^o$ indicates the reduced form is more stable than H₂ (stronger oxidizing agent), while a negative $E^o$ indicates H₂ is more stable than the reduced form (stronger reducing agent). Standard electrode potentials help predict the feasibility of reactions and compare the oxidizing/reducing strengths of species.
Nernst Equation
The Nernst equation relates the electrode potential ($E$) of a half-cell or the cell potential ($E_{cell}$) to the concentrations of the species involved and the standard electrode potential ($E^o$). For a general electrode reaction $M^{n+} + ne^- \rightarrow M(s)$, the electrode potential is $E_{M^{n+}/M} = E^o_{M^{n+}/M} - \frac{RT}{nF} \ln \frac{1}{[M^{n+}]}$. For a cell reaction, $aA + bB \rightarrow cC + dD$, the cell potential is $E_{cell} = E^o_{cell} - \frac{RT}{nF} \ln Q$, where $Q = \frac{[C]^c [D]^d}{[A]^a [B]^b}$ is the reaction quotient.
At 298 K, the equation simplifies to $E_{cell} = E^o_{cell} - \frac{0.0591}{n} \log Q$. The cell potential is positive and the reaction is spontaneous as long as $E_{cell} > 0$. As the reaction proceeds, concentrations change, $E_{cell}$ decreases, and eventually, $E_{cell}$ becomes zero at equilibrium.
Equilibrium Constant From Nernst Equation
At equilibrium, $E_{cell} = 0$ and $Q = K_c$ (equilibrium constant). Substituting these into the Nernst equation gives $E^o_{cell} = \frac{2.303RT}{nF} \log K_c$. At 298 K, $E^o_{cell} = \frac{0.0591}{n} \log K_c$. This equation allows calculation of the equilibrium constant from the standard cell potential.
Electrochemical Cell And Gibbs Energy Of The Reaction
The standard Gibbs energy change ($Δ^o_rG$) of a cell reaction is related to the standard cell potential ($E^o_{cell}$) by the equation $Δ^o_rG = -nFE^o_{cell}$, where $n$ is the number of moles of electrons transferred and $F$ is the Faraday constant. Gibbs energy also relates to the equilibrium constant ($Δ^o_rG = -RT \ln K_c$). Thus, $E^o_{cell}$ provides thermodynamic information about the reaction.
Conductance Of Electrolytic Solutions
Electrolytic solutions conduct electricity due to the movement of ions. Conductivity ($κ$) is the inverse of resistivity ($ρ$), and molar conductivity ($Λ_m$) is the conductivity per mole of electrolyte. Both decrease with decreasing concentration for strong electrolytes (due to decreased number of ions per unit volume) and increase steeply for weak electrolytes (due to increased dissociation).
Measurement Of The Conductivity Of Ionic Solutions
The resistance of an electrolytic solution is measured using a conductivity cell with two platinum electrodes coated with platinum black, immersed in the solution. The cell constant ($G^* = l/A$) is determined by measuring the resistance of a solution with known conductivity. The conductivity ($κ$) is then calculated as $κ = G^* / R$, where $R$ is the measured resistance.
Variation Of Conductivity And Molar Conductivity With Concentration
Conductivity ($κ$): Decreases with dilution because the number of ions per unit volume decreases. This trend holds for both strong and weak electrolytes.
Molar Conductivity ($Λ_m$): Increases with dilution. For strong electrolytes, this increase is gradual ($Λ_m = Λ^o_m - A\sqrt{c}$), attributed to increased volume of solution per mole of electrolyte. For weak electrolytes, the increase is steep, mainly due to increased dissociation. The molar conductivity at infinite dilution ($Λ^o_m$) is the theoretical maximum value where dissociation is complete.
Kohlrausch's Law: States that the limiting molar conductivity of an electrolyte is the sum of the contributions of its individual ions ($Λ^o_m = ν_+ λ^o_+ + ν_- λ^o_-$). This law is useful for calculating $Λ^o_m$ for weak electrolytes and determining ionic conductivities.
Electrolytic Cells And Electrolysis
Electrolytic cells use external electrical energy to drive non-spontaneous redox reactions. Electrolysis involves using direct current to decompose electrolytes. The products formed depend on the electrolyte's nature, concentration, and the electrode material (inert vs. reactive).
Faraday's Laws of Electrolysis:
- First Law: The amount of chemical reaction at an electrode is proportional to the quantity of electricity passed ($Q = It$).
- Second Law: The amounts of different substances liberated by the same quantity of electricity are proportional to their equivalent weights.
One Faraday of charge (96487 C) deposits or liberates one equivalent weight of substance. For instance, depositing 1 mole of Cu requires 2 moles of electrons (2F), while 1 mole of Ag requires 1 mole of electron (1F).
Products Of Electrolysis
The products of electrolysis depend on factors like the ions present, their standard electrode potentials ($E^o$), and overpotential. For example, electrolysis of aqueous NaCl yields H₂ at the cathode and Cl₂ at the anode (due to overpotential of oxygen making Cl⁻ oxidation more favorable than water oxidation). Electrolysis of molten NaCl yields Na metal and Cl₂ gas. The electrolysis of aqueous solutions can also produce or consume H⁺/OH⁻ ions, affecting the solution's pH.
Batteries
Batteries are galvanic cells used as portable sources of electrical energy. They convert chemical energy into electrical energy through spontaneous redox reactions.
Primary Batteries
Primary cells are used once and cannot be recharged. The redox reaction is irreversible. Examples include the:
- Dry Cell (Leclanché cell): Zn anode, C (graphite) cathode with MnO₂ and C powder, electrolyte is NH₄Cl + ZnCl₂ paste. $E \approx 1.5 V$.
- Mercury Cell: Zn-amalgam anode, paste of HgO and C cathode, KOH+ZnO electrolyte. $E \approx 1.35 V$. It provides a constant voltage throughout its life.
Secondary Batteries
Secondary cells can be recharged by passing current in the reverse direction, allowing reuse. Examples include:
- Lead Storage Battery: Pb anode, PbO₂ cathode, H₂SO₄ electrolyte. Used in cars and inverters. The reaction involves PbSO₄ formation at both electrodes during discharge, which reverts to Pb and PbO₂ upon charging.
- Nickel-Cadmium (Ni-Cd) Cell: A rechargeable cell with a longer life than lead-acid batteries but is more expensive.
Fuel Cells
Fuel cells are galvanic cells that directly convert the chemical energy of fuel combustion into electrical energy, offering higher efficiency (~70%) and being pollution-free compared to thermal power plants (~40%). Reactants (fuel and oxidant) are continuously supplied, and products are removed. The most common fuel cell uses hydrogen and oxygen, producing water. Catalysts (like Pt or Pd) are used at porous electrodes to increase reaction rates. The reaction is $2H_2(g) + O_2(g) \rightarrow 2H_2O(l)$, generating electricity continuously as long as reactants are supplied.
Corrosion
Corrosion is the gradual destruction of metals through chemical or electrochemical reactions with their environment. Rusting of iron is a common example, involving the oxidation of iron and reduction of oxygen in the presence of water and electrolytes (like CO₂ dissolved in water forming carbonic acid).
Electrochemical Mechanism of Rusting: Iron acts as an anode where oxidation occurs: $Fe(s) \rightarrow Fe^{2+}(aq) + 2e^-$ ($E^o = -0.44$ V). Electrons flow through the metal to a cathodic region where reduction of oxygen occurs: $O_2(g) + 4H^+(aq) + 4e^- \rightarrow 2H_2O(l)$ ($E^o = +1.23$ V). The overall cell potential is $E^o_{cell} = 1.67$ V, indicating spontaneity. $Fe^{2+}$ ions are further oxidized to $Fe^{3+}$, which forms hydrated ferric oxide ($Fe_2O_3 \cdot xH_2O$), the rust.
Prevention: Corrosion can be prevented by preventing contact with the atmosphere (painting, coating with inert metals like tin) or by using sacrificial anodes (more reactive metals like Mg or Zn) that corrode preferentially, protecting the main object.
Intext Questions
Question 2.1. How would you determine the standard electrode potential of the system $Mg^{2+}|Mg$?
Answer:
Question 2.2. Can you store copper sulphate solutions in a zinc pot?
Answer:
Question 2.3. Consult the table of standard electrode potentials and suggest three substances that can oxidise ferrous ions under suitable conditions.
Answer:
Question 2.4. Calculate the potential of hydrogen electrode in contact with a solution whose pH is 10.
Answer:
Question 2.5. Calculate the emf of the cell in which the following reaction takes place:
$Ni(s) + 2Ag^+ (0.002 M) \rightarrow Ni^{2+} (0.160 M) + 2Ag(s)$
Given that $E^\circ_{cell} = 1.05 \text{ V}$
Answer:
Question 2.6. The cell in which the following reaction occurs:
$2Fe^{3+}(aq) + 2I^-(aq) \rightarrow 2Fe^{2+}(aq) + I_2(s)$
has $E^\circ_{cell} = 0.236 \text{ V}$ at 298 K. Calculate the standard Gibbs energy and the equilibrium constant of the cell reaction.
Answer:
Question 2.7. Why does the conductivity of a solution decrease with dilution?
Answer:
Question 2.8. Suggest a way to determine the $\Lambda_m^\circ$ value of water.
Answer:
Question 2.9. The molar conductivity of 0.025 mol L$^{–1}$ methanoic acid is 46.1 S cm$^2$ mol$^{–1}$. Calculate its degree of dissociation and dissociation constant. Given $\lambda^0(H^+) = 349.6 \text{ S cm}^2 \text{ mol}^{–1}$ and $\lambda^0(HCOO^–) = 54.6 \text{ S cm}^2 \text{ mol}^{–1}$.
Answer:
Question 2.10. If a current of 0.5 ampere flows through a metallic wire for 2 hours, then how many electrons would flow through the wire?
Answer:
Question 2.11. Suggest a list of metals that are extracted electrolytically.
Answer:
Question 2.12. Consider the reaction: $Cr_2O_7^{2-} + 14H^+ + 6e^- \rightarrow 2Cr^{3+} + 7H_2O$
What is the quantity of electricity in coulombs needed to reduce 1 mol of $Cr_2O_7^{2-}$?
Answer:
Question 2.13. Write the chemistry of recharging the lead storage battery, highlighting all the materials that are involved during recharging.
Answer:
Question 2.14. Suggest two materials other than hydrogen that can be used as fuels in fuel cells.
Answer:
Question 2.15. Explain how rusting of iron is envisaged as setting up of an electrochemical cell.
Answer:
Exercises
Question 2.1. Arrange the following metals in the order in which they displace each other from the solution of their salts.
Al, Cu, Fe, Mg and Zn.
Answer:
Question 2.2. Given the standard electrode potentials,
$K^+/K = –2.93V, Ag^+/Ag = 0.80V,$
$Hg^{2+}/Hg = 0.79V$
$Mg^{2+}/Mg = –2.37 V, Cr^{3+}/Cr = – 0.74V$
Arrange these metals in their increasing order of reducing power.
Answer:
Question 2.3. Depict the galvanic cell in which the reaction $Zn(s)+2Ag^+(aq) \rightarrow Zn^{2+}(aq)+2Ag(s)$ takes place. Further show:
(i) Which of the electrode is negatively charged?
(ii) The carriers of the current in the cell.
(iii) Individual reaction at each electrode.
Answer:
Question 2.4. Calculate the standard cell potentials of galvanic cell in which the following reactions take place:
(i) $2Cr(s) + 3Cd^{2+}(aq) \rightarrow 2Cr^{3+}(aq) + 3Cd$
(ii) $Fe^{2+}(aq) + Ag^+(aq) \rightarrow Fe^{3+}(aq) + Ag(s)$
Calculate the $\Delta_rG^\circ$ and equilibrium constant of the reactions.
Answer:
Question 2.5. Write the Nernst equation and emf of the following cells at 298 K:
(i) $Mg(s)|Mg^{2+}(0.001M)||Cu^{2+}(0.0001 M)|Cu(s)$
(ii) $Fe(s)|Fe^{2+}(0.001M)||H^+(1M)|H_2(g)(1bar)| Pt(s)$
(iii) $Sn(s)|Sn^{2+}(0.050 M)||H^+(0.020 M)|H_2(g) (1 bar)|Pt(s)$
(iv) $Pt(s)|Br^-(0.010 M)|Br_2(l )||H^+(0.030 M)| H_2(g) (1 bar)|Pt(s)$.
Answer:
Question 2.6. In the button cells widely used in watches and other devices the following reaction takes place:
$Zn(s) + Ag_2O(s) + H_2O(l) \rightarrow Zn^{2+}(aq) + 2Ag(s) + 2OH^-(aq)$
Determine $\Delta_rG^\circ$ and $E^\circ$ for the reaction.
Answer:
Question 2.7. Define conductivity and molar conductivity for the solution of an electrolyte. Discuss their variation with concentration.
Answer:
Question 2.8. The conductivity of 0.20 M solution of KCl at 298 K is 0.0248 S cm$^{–1}$. Calculate its molar conductivity.
Answer:
Question 2.9. The resistance of a conductivity cell containing 0.001M KCl solution at 298 K is 1500 $\Omega$. What is the cell constant if conductivity of 0.001M KCl solution at 298 K is $0.146 \times 10^{–3} \text{ S cm}^{–1}$.
Answer:
Question 2.10. The conductivity of sodium chloride at 298 K has been determined at different concentrations and the results are given below:
| Concentration/M | $10^2 \times \kappa / S m^{–1}$ |
|---|---|
| 0.001 | 1.237 |
| 0.010 | 11.85 |
| 0.020 | 23.15 |
| 0.050 | 55.53 |
| 0.100 | 106.74 |
Calculate $\Lambda_m$ for all concentrations and draw a plot between $\Lambda_m$ and $c^{1/2}$. Find the value of $\Lambda_m^\circ$.
Answer:
Question 2.11. Conductivity of 0.00241 M acetic acid is $7.896 \times 10^{–5} \text{ S cm}^{–1}$. Calculate its molar conductivity. If $\Lambda_m^\circ$ for acetic acid is 390.5 S $cm^2$ $mol^{–1}$, what is its dissociation constant?
Answer:
Question 2.12. How much charge is required for the following reductions:
(i) 1 mol of $Al^{3+}$ to Al?
(ii) 1 mol of $Cu^{2+}$ to Cu?
(iii) 1 mol of $MnO_4^-$ to $Mn^{2+}$?
Answer:
Question 2.13. How much electricity in terms of Faraday is required to produce
(i) 20.0 g of Ca from molten $CaCl_2$?
(ii) 40.0 g of Al from molten $Al_2O_3$?
Answer:
Question 2.14. How much electricity is required in coulomb for the oxidation of
(i) 1 mol of $H_2O$ to $O_2$?
(ii) 1 mol of FeO to $Fe_2O_3$?
Answer:
Question 2.15. A solution of $Ni(NO_3)_2$ is electrolysed between platinum electrodes using a current of 5 amperes for 20 minutes. What mass of Ni is deposited at the cathode?
Answer:
Question 2.16. Three electrolytic cells A,B,C containing solutions of $ZnSO_4$, $AgNO_3$ and $CuSO_4$, respectively are connected in series. A steady current of 1.5 amperes was passed through them until 1.45 g of silver deposited at the cathode of cell B. How long did the current flow? What mass of copper and zinc were deposited?
Answer:
Question 2.17. Using the standard electrode potentials given in Table 3.1, predict if the reaction between the following is feasible:
(i) $Fe^{3+}(aq)$ and $I^-(aq)$
(ii) $Ag^+(aq)$ and Cu(s)
(iii) $Fe^{3+}(aq)$ and $Br^-(aq)$
(iv) Ag(s) and $Fe^{3+}(aq)$
(v) $Br_2(aq)$ and $Fe^{2+}(aq)$.
Answer:
Question 2.18. Predict the products of electrolysis in each of the following:
(i) An aqueous solution of $AgNO_3$ with silver electrodes.
(ii) An aqueous solution of $AgNO_3$ with platinum electrodes.
(iii) A dilute solution of $H_2SO_4$ with platinum electrodes.
(iv) An aqueous solution of $CuCl_2$ with platinum electrodes.
Answer: